Vowels are very essential characters to form any meaningful word in English dictionary. There are 5 vowels in English language - a, e, i, o u. You are given a randoms string containing only lowercase letters and you need to find if the string contains ALL the vowels.
Input:
FIrst line contains N , the size of the string.
Second line contains the letters (only lowercase).
Output:
Print "YES" (without the quotes) if all vowels are found in the string, "NO" (without the quotes) otherwise.
Constraints:
The size of the string will not be greater than 10,000
1 ≤ N ≤ 10000
C Implementation:
Input:
FIrst line contains N , the size of the string.
Second line contains the letters (only lowercase).
Output:
Print "YES" (without the quotes) if all vowels are found in the string, "NO" (without the quotes) otherwise.
Constraints:
The size of the string will not be greater than 10,000
1 ≤ N ≤ 10000
C Implementation:
#include <stdio.h>
int main()
{
     int n;
     char *s;
     int hash[26];
     int i;
     scanf("%d",&n);
     s=(char*)malloc(sizeof(char)*1000000);
     scanf("%s",s);
     memset(hash,0,sizeof(hash));
     i=0;
     while(*(s+i))
     {
          hash[*(s+i)-'a']++;
          i++;
     }
     if(hash['a'-'a'] && hash['e'-'a'] && hash['i'-'a'] && hash['o'-'a'] && hash['u'-'a'])
          printf("YES");
     else
          printf("NO");
     return 0;
}
Output:
8
atuongih
NO