Java program to arrange numbers in ascending order

Java program to arrange numbers in ascending order

Output:

Enter the number of elements to sort: 10
Enter the numbers to sort:
10 9 8 7 6 5 4 3 2 1
The Sorted Array is:
1 2 3 4 5 6 7 8 9 10

Implementation:

import java.util.*; import java.lang.*; import java.io.*; class CodeRegister { public static void sortArray(int[] array) { int n=array.length; for(int i=0;i<n-1;i++) { for(int j=i+1;j<n;j++) { if(array[i] > array[j]) { swapPair(array,i,j); } } } } public static void swapPair(int[] array,int i,int j) { int temp; temp=array[i]; array[i]=array[j]; array[j]=temp; } public static void main (String[] args) throws java.lang.Exception { Scanner in = new Scanner(System.in); int[] array; int n; System.out.println("Enter the number of elements to sort:"); n = in.nextInt(); array = new int[n]; System.out.println("Enter the numbers to sort:"); for(int i=0;i<n;i++) { array[i] = in.nextInt(); } sortArray(array); /* Printing the sorted array */ System.out.println("The Sorted Array is:"); for(int i=0;i<n;i++) { System.out.print(array[i]+" "); } } }