C program to print given number in words using switch

C program to print given number in words using switch

Output:

Enter the number:
1234
The number 1234 in words is : One Two Three Four

Implementation:

#include <stdio.h> int main(void) { char str[1000]; int i; printf("Enter the number:\n"); scanf("%s",str); printf("The number %s in words is : ",str); for(i=0;*(str+i);i++) { switch(str[i]) { case '1': printf("One "); break; case '2': printf("Two "); break; case '3': printf("Three "); break; case '4': printf("Four "); break; case '5': printf("Five "); break; case '6': printf("Six "); break; case '7': printf("Seven "); break; case '8': printf("Eight "); break; case '9': printf("Nine "); break; case '0': printf("Zero "); break; } } return 0; }