C program to find nth power of a matrix

C program to find nth power of a matrix


Input:

Enter the elements of matrix:
1 2 3
4 5 6
7 8 9
Enter the power:
3

Output:

1       8     27
64    125  216
343  512  729

Implementation:

#include <stdio.h> #include <math.h> #include <stdlib.h> #define r 3 // set the row size here #define c 3 // set the column size here int main(void) { int n; int i,j; int a[r][c]; printf("Enter the elements of matrix:\n"); for(i=0;i<r;i++) { for(j=0;j<c;j++) { scanf("%d",&a[i][j]); } } printf("Enter the power:\n"); scanf("%d",&n); /* find nth power of matrix i.e., if the given matrix is 1 2 3 4 5 6 7 8 9 then if the power is given as 2, then the result matrix would be result of each element of the matrix raised to power of 2 i.e., 1 4 9 16 25 36 49 64 81*/ for(i=0;i<r;i++) { for(j=0;j<c;j++) { a[i][j]=pow(a[i][j],n); } } /* printing the nth power (result matrix) */ for(i=0;i<r;i++) { for(j=0;j<c;j++) { printf("%d ",a[i][j]); } printf("\n"); } return 0; }