C program to calculate a^b

C program to calculate a^b

Output:

Enter the number a: 5
Enter the number b: 5
The ex-or product of 5 ^ 5 is 0

Implementation:

/* If you want to find pow(a,b) or a raised to the power of b visit the link: http://www.coderegister.co.in/2015/09/c-program-to-find-nth-power-of-number.html Else if you want to find the ex-or product of a and b go on reading the following article EX-OR TABLE: ----------- A B A^B ------------ 0 0 0 0 1 1 1 0 1 1 1 0 */ #include <stdio.h> int main(void) { int a,b; printf("Enter the number a:\n"); scanf("%d",&a); printf("Enter the number b:\n"); scanf("%d",&b); printf("The ex-or product of %d ^ %d is %d",a,b,(a^b)); return 0; }