C program to swap two numbers using call by reference

C program to swap two numbers using call by reference

Output:

Enter the two values to swap:
5 6
Before swapping:
a=5 b=6
After swapping:
a=6 b=5

Implementation:

#include <stdio.h> void swap(int *x,int *y) { int temp; temp=*x; *x=*y; *y=temp; } int main(void) { int a,b; printf("Enter the two values to swap:\n"); scanf("%d %d",&a,&b); printf("Before swapping:\n"); printf("a=%d b=%d\n",a,b); swap(&a,&b); printf("After swapping:\n"); printf("a=%d b=%d",a,b); return 0; }