C program to swap two numbers using pointers

C program to swap two numbers using pointers

Output:

Enter two numbers to swap:
4 5
Before swapping:
a=4 b=5
After swapping:
a=5 b=4

Implementation:

#include <stdio.h> int main(void) { int a,b,c; int *x,*y; printf("Enter two numbers to swap:\n"); scanf("%d %d",&a,&b); printf("Before swapping:\n"); printf("a=%d b=%d\n",a,b); x=&a; y=&b; c=*x; *x=*y; *y=c; printf("After swapping:\n"); printf("a=%d b=%d",a,b); return 0; }