Sum of all the elements of the matrix

Sum of all the elements of the matrix


Input:

1 2 3
4 5 6
7 8 9

Output:

The sum of all the elements of the matrix is: 45

Implementation:

#include <stdio.h> #include <stdlib.h> #define r 2 #define c 2 int findsum(int *a[]) { int i,j,sum=0; for(i=0;i<r;i++) { for(j=0;j<c;j++) { sum+= *(*(a+i)+j); } } return sum; } int main(void) { /* give the input array while writing the code (static initialization) */ int *a[r]; int i,j,element; /* memory allocation for 2-D array using malloc() function */ for(i=0;i<r;i++) *(a+i)=(int*)malloc(sizeof(int)*c); /* get the input array elements from the user */ for(i=0;i<r;i++) { for(j=0;j<c;j++) { scanf("%d",(*(a+i)+j)); } } /* function call to print the sum of all the elements in the matrix */ printf("The sum of all the elements of the matrix is %d",findsum(a)); return 0; }