Given two sorted arrays, merge them into single array such that the elements are not repeated

Given two sorted arrays, merge them into single array such that the elements are not repeated.



For Example:

Input:

          Array1: 2 4 5 6 7 9 10 13

          Array2: 2 3 4 5 6 7 8 9 11 15

Output: 2 3 4 5 6 7 8 9 10 11 13 15

Implementation:

#include<stdio.h>
#include<stdlib.h>
int main()
{
  int *s,*v,*c;
  int n,x;
  int l,r,t;
  int i;
  
  /* Get the size of the first sorted array */
  scanf("%d",&n);
  
  /* allocate memory for the first array */
  s=(int*)malloc(sizeof(int)*n);
  
  /* Get the size of the second sorted array */
  scanf("%d",&x);
  
  /* allocate memory for the second array */
  v=(int*)malloc(sizeof(int)*x);
  
  /* Get the values of the first sorted array */
  for(i=0;i<n;i++)
    scanf("%d",(s+i));
   
   /* Get the values of the second sorted array */
  for(i=0;i<x;i++)
    scanf("%d",(v+i));
   
   /* Allocate memory for the resultant array */
  c=(int*)malloc(sizeof(int)*(n+x));
  
  /* Initialize counter variables for array1, array2, result array */
  l=0;
  r=0;
  t=0;
  
  /* Until we reach the end of any one of the array */
  while(l<n && r<x)
  {
   
   /* Check if the value of the both arrays are equal
   If yes, copy value from any one of the array */
    if(*(s+l)==*(v+r))
    {
      c[t++]=*(s+l);
      
      /* Increment both of the array pointers */
      l++;
      r++;
    }
    
    /* If the value of array1 is less than the value of array2
    copy the value of array1 & move the pointer of array 1*/
    else if(*(s+l)<*(v+r))
    {
      c[t++]=*(s+l);
      l++;
    }
    
    /* Else copy the value of array2 & move the pointer of array2*/
    else
    {
      c[t++]=*(v+r);
      r++;
    }
  }
  
  /* We reached the end of array 1*/
  if(l==n)
  {
   
   /* But yet we did't reached the end of array 2 */
    while(r<x)
    {
     
     /* Copy all the remaining elements of array 2 to result array */
      c[t++]=*(v+r);
      r++;
    }
  }
  else
  {
    while(l<n)
    {
     
     /* Else, copy all the remaining elements of array 1 to result array */
      c[t++]=*(s+l);
      l++;
    }
  }
  
  /* Print the result array */
  for(i=0;i<t;i++)
    printf("%d ",*(c+i));
  
  return 0;
}

Input:

8
10
2 4 5 6 7 9 10 13
2 3 4 5 6 7 8 9 11 15

Output:

2 3 4 5 6 7 8 9 10 11 13 15