Given a number N, you have to find the sum of fibonacci numbers starting from 2 till N. i.e., if N = 2 , sum=5 (2 + 3). Let us consider one more example. If N=3, sum = 10 (2 + 3 + 5)
Method 1:
Set sum = 2 and starting from 1 loop until N, calculate the fibonacci series & add the numbers to sum.
Implementation:
#include <stdio.h>
int main()
{
    int t;
    scanf("%d",&t);
    while(t--)
    {
     int n,res=0,i,prev,curr,next;
     scanf("%d",&n);
     prev=1;
     curr=1;
     for(i=1;i<=n;i++)
     {
      next=prev+curr;
      res=res+next;
      prev=curr;
      curr=next;
      
     }
     printf("%d\n",(res % 1000000007) );
    }
    return 0;
}
Input
First line - T, the number of test cases.
Each of next T lines contains single integer N.
First line - T, the number of test cases.
Each of next T lines contains single integer N.
Output
Sum till Nth Fibonacci Number
Sample Input
2
2
3
Sample Output
5
10