Given a number 'N', check & print the Fibonacci numbers from 1 to N

 Write a function that receives the Number and set the number as range. Now starting from 1 till the range, print "IsFibo" if a number is a Fibonacci number or "IsNotFibo", if a number is not a Fibonacci number.


Implementation:

#include<stdio.h> #include<math.h> int isperfect(int perno) { int s; s=sqrt(perno); return (s*s==perno); } int isfibo(int no) { return (isperfect(5*no*no+4)||isperfect(5*no*no-4)); } int main() { int no,status,i,x,j; printf("Enter the range:\n"); scanf("%d",&x); for(i=0;i<=x;i++) { status=isfibo(i); if(status = =1) printf("IsFibo\n"); else printf("IsNotFibo\n"); } return 0; }

Output:
Enter the range:
10
IsFibo
IsFibo
IsFibo
IsFibo
IsNotFibo
IsFibo
IsNotFibo
IsNotFibo
IsFibo
IsNotFibo
IsNotFibo